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Mathematical Logic+UnSolved



Thursday, January 23, 2020

(PVQ)^(P->R)^(q->R)is equivalent to

(PVQ)^(P->R)^(q->R)is equivalent to
AP
Bq
CR
DTrue = T.
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P, Q, R are three languages. PQ = R and P and R are regular.

P, Q, R are three languages. PQ = R and P and R are regular. This implies
AQ has to be regular
BQ cannot be regular
CQ need not be regular
DQ cannot be a CFL
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